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21x^2-63x-68=0
a = 21; b = -63; c = -68;
Δ = b2-4ac
Δ = -632-4·21·(-68)
Δ = 9681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{9681}}{2*21}=\frac{63-\sqrt{9681}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{9681}}{2*21}=\frac{63+\sqrt{9681}}{42} $
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